暴力做法是对每个位置向右扫描找第一个更大值，O(n²)。可抽象为：元素像一排人，身高为数值。当前人「下一个更大」= 他右侧第一个没被挡住的人（比当前矮的都被挡住）。单调栈用 O(n) 维护「右侧候选更大值」：倒序遍历，弹掉 ≤ 当前的，栈顶即答案，再入栈当前值。
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Eventually, I found the resvg testsuite, which has broad coverage and is refreshingly easy to work with. In my unscientific self-evaluation, GtkSvg passes 1250 of the 1616 tests in this testsuite now, which puts GTK one tier below where the web browsers are. It would be nice to catch up with them, but that will require closing some gaps in our rendering infrastructure to support more complex filters.。业内人士推荐快连下载-Letsvpn下载作为进阶阅读