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If you wanted to find an exact match, you could try aideal = r · b; this makes the a / b fraction equal to r · b / b = r. That said, r · b might not be an integer (or even a rational number), so even without the added constraint, the approach is usually a bust.
也正是这个痛点，网络上催生了围绕 OpenClaw 的一批省钱攻略。
if urlparse(u).netloc != urlparse(BASE).netloc: